Nuprl Lemma : last-cons 11,40

x:top, as:(top List). sqequal(last(cons(xas)); if null(as) then x else last(as) fi ) 
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Definitionshd(l), i <z j, i j, l[i], last(L), top, t  T, x:AB(x), ge(ij), P  Q, False, A, A  B, P  Q, lelt(ijk), int_seg(ij), ||as||
Lemmasselect cons tl sq, length cons, non neg length, length wf1, top wf

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